The correct option is D (4,5,–2)
Let P≡(1,8,4)
Equation of line joining points (0,–11,4) and (2,–3,1)
x−22=y+38=z−1−3=λ
Any point on the line is Q(2λ+2,8λ−3,1−3λ)
DR's of PQ(2λ+1,8λ−11,−3λ−3)
Now PQ⊥ to the line
∴(2λ+1)2+(8λ−11)8+(−3λ−3)(−3)=0
77λ−77=0⇒λ=1
Q(4,5,–2)