Question

The foot of the perpendicular from $(7,14,5)$ to $2x+4y-z=2$ is

• A. $(-1,1,0)$
• B. $(1,2,8)$
• C. $(2,-1,-2)$
• D. $(1,2,3)$

Answer 1

The correct option is B $(1,2,8)$

Given that,

$(7,14,5)$ $2x+4y-z=2$

$\begin{array}{c}\frac{x-7}{2}=\frac{y-14}{4}=\frac{z-5}{-1}=\frac{-\left(14+56-5-2\right)}{21}\\ \frac{x-7}{2}=\frac{y-14}{4}=\frac{z-5}{-1}=-3\\ \left(1,2,8\right)\end{array}$

Then,

Option $B$ is correct answer.