Question

The force acting on an object varies with the distance travelled by the object as shown in Fig. Work done by the force in moving the object from $x=2m$ to $x=4m$ is?

• A. $\frac{4}{3}$ J
• B. $6$ J
• C. $8$ J
• D. $2$ J

Answer 1

The correct option is A $\frac{4}{3}$ J

Work done =area enclosed from $x=2$ to $4m$

$=\frac{1}{2}(4-2)\times \left[\frac{4}{6}\right(4-2\left)\right]$

$=1\times \frac{8}{6}=\frac{4}{3}J$