The force acting on each pole of a magnet when placed in a uniform magnetic field of 7 A-m is 4-2- 10-4N- If the distance between the poles is 10 cm- the moment of the magnet is

The correct option is A 15π ...

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Standard XII

Physics

More about Magnetic Dipoles

The force act...

Question

The force acting on each pole of a magnet when placed in a uniform magnetic field of $7 A / m$ is $4.2 \times 10^{- 4} N$ . If the distance between the poles is $10 cm$, the moment of the magnet is

\frac{15}{π}

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\frac{π}{15} A m^{2}

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7.5 \times 10^{- 12} A m^{2}

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6 \times 10^{- 6} A m^{2}

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Solution

The correct option is A $\frac{15}{π}$

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The force acting on each pole of a magnet when placed in a uniform magnetic field of 7A/m is 4.2×10−4N. If the distance between the poles is $10 cm$, the moment of the magnet is

The correct option is A 15π

The force acting on each pole of a magnet when placed in a uniform magnetic field of $7 A / m$ is $4.2 \times 10^{- 4} N$ . If the distance between the poles is $10 cm$, the moment of the magnet is

The correct option is A $\frac{15}{π}$