The force between two alpha particles separated by a distance r is f.in order to have same force f the distance between singly ionized chlorine atoms separated by a distance of
1. 2r
2.4r
3.r/2
4.r/4
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Solution
Charge on a alpha particle = 3.20×10-19 C K(3.20×10-19)2/r2=F
Let the distance between the Chlorine atoms be R. charge on a single ionized = 1.6×10-19 C Therefore, the force = K(1.6×10-19)2/R2 =F/K=(3.20×10-19)2/r2 =4(1.6×10-19)2/r2=(1.6×10-19)2/R2 R= r/2.