The force between two parallel conductors, each of length 50cm and distant 20cm apart is 100 N. If the current in one conductor is double that in another one then the values will respectively be(Given μ0=4π×10−7)
A
104A and 2×104A
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B
50A and 100A
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C
10A and 20A
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D
5A and 10A
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Solution
The correct option is A104A and 2×104A F=μ0i1i2l2πr 100=2×10−7×2i×1×⋅5⋅2 108=i2 i=104Amp Current in other wire =2i=2×104Amp