wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

The force between two parallel current carrying conductors separated by a distance x is F. If the current in each conductor is doubled and the distance between them is halved, then the force between them becomes.

A
F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8F
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8F
Given
Two parallel wires having current i1 and i2
Distance between them is x
Force between them is F
length of two wires is L
Solution
Force between wires is
F=μ0i1i2L2πx
We can see that
F is directly proportional to product of currents
F is inversely proportional to x
So if we double the currents F will become 4 times
And if we halved the x, F will become 2 times
if we combine F become 8 times
The correct option is D


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parallel Currents
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon