The force between two parallel current carrying conductors separated by a distance x is F. If the current in each conductor is doubled and the distance between them is halved, then the force between them becomes.
A
F
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B
2F
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C
4F
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D
8F
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Solution
The correct option is D8F Given
Two parallel wires having current i1 and i2
Distance between them is x
Force between them is F
length of two wires is L
Solution
Force between wires is
F=μ0i1∗i2∗L2πx
We can see that
F is directly proportional to product of currents
F is inversely proportional to x
So if we double the currents F will become 4 times