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Byju's Answer

Standard XII

Physics

Work Done: Spring

The force con...

Question

The force constant of a wire is k and that of another wire is 2k. When both the wires are stretched through same distance, then the work done

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Solution

The correct option is B

$W = \frac{1}{2} k x^{2}$

If both wires are stretched through same distance then

$W α k . A s k_{2} = 2 k_{1}$ so $W_{2} = 2 W_{1}$

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The force constant of a wire is k and that of another wire is 2k. When both the wires are stretched through same distance, then the work done

The correct option is B W=12kx2 If both wires are stretched through same distance then Wα k. As k2=2k1 so W2=2W1

The correct option is B

$W = \frac{1}{2} k x^{2}$

If both wires are stretched through same distance then

$W α k . A s k_{2} = 2 k_{1}$ so $W_{2} = 2 W_{1}$