The force exerted by an electric field on a charge of 3 micro-coulomb is 6 - 10-4 N- What is the electric intensity of the field-

We know F = qE ⇒ E = Fq ⇒ E = 6 × 10^ 43 × 10^ 6 ⇒ E = 200 V/m ...

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Standard XII

Physics

Understanding Electrostatic Potential

The force exe...

Question

The force exerted by an electric field on a charge of 3 micro-coulomb is $6 \times 10^{- 4}$ N. What is the electric intensity of the field?

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Solution

We know $F = q E$
$\Rightarrow E = \frac{F}{q}$

$\Rightarrow E = \frac{6 \times 10^{- 4}}{3 \times 10^{- 6}}$

$\Rightarrow E = 200 V / m$

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The force exerted by an electric field on a charge of 3 micro-coulomb is 6×10−4 N. What is the electric intensity of the field?

We know F=qE⇒E=Fq⇒E=6×10−43×10−6⇒E=200V/m

The force exerted by an electric field on a charge of 3 micro-coulomb is $6 \times 10^{- 4}$ N. What is the electric intensity of the field?

We know $F = q E$
$\Rightarrow E = \frac{F}{q}$

$\Rightarrow E = \frac{6 \times 10^{- 4}}{3 \times 10^{- 6}}$

$\Rightarrow E = 200 V / m$