Question

The force exerted by an electric field on a charge of 3 micro-coulomb is $6x{10}^{-4}N$. What is the electric intensity of the field?

Answer 1

Electric field $E=\frac{F}{q}$

or $E=\frac{6\times {10}^{-4}}{3\times {10}^{-6}}=200N/C$