The force exerted by an electric field on a charge of 5 micro-coulomb is 10 - 10-4 N- What is the electric intensity of the field at the point -

Electric field #160; #160; #160; E = Fq Or #160; #160; #160; E = 10× 10^ 45× 10^ 6 = 200 N/C ...

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Standard XII

Physics

Torque on a Dipole

The force exe...

Question

The force exerted by an electric field on a charge of 5 micro-coulomb is $10 \times 10^{- 4}$ N. What is the electric intensity of the field at the point ?

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Solution

Electric field $E = \frac{F}{q}$
Or $E = \frac{10 \times 10^{- 4}}{5 \times 10^{- 6}} = 200 N / C$

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The force exerted by an electric field on a charge of 5 micro-coulomb is 10×10−4 N. What is the electric intensity of the field at the point ?

Electric field E=FqOr E=10×10−45×10−6=200 N/C

The force exerted by an electric field on a charge of 5 micro-coulomb is $10 \times 10^{- 4}$ N. What is the electric intensity of the field at the point ?

Electric field $E = \frac{F}{q}$
Or $E = \frac{10 \times 10^{- 4}}{5 \times 10^{- 6}} = 200 N / C$