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Second Law of Motion

The force exe...

Question

The force exerted on $5 kg$ block by $10 kg$ block placed in the lift, shown in the figure is

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Solution

FBD of $5 kg$ block

$∴$ Force exerted on $5 kg$ by $10 kg$ block is $N_{2}$

Net force on $5 kg$ block is zero w.r.t to lift frame.
$N_{2} - 5 g - 15 = 0$
or $N_{2} = 65 N$

Hence, Option $(C)$ is the correct answer.

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