Question

The force exerted to pull a cart is equal the mass of the body multiplied by the acceleration produced in the body. Express the statement as a linear equation of two variables and draw the graph of the same by taking the constant mass equal to $6$ kg. Read from the graph, the force required when the acceleration produced is $5m/se{c}^2$

• A. $y=m$, where $y$ denotes the force, $x$ denotes the acceleration and $m$ denotes the constant mass$;$ $20$ newton
• B. $y=mx$, where $y$ denotes the force, $x$ denotes the acceleration and $m$ denotes the constant mass$;$ $30$ newton
• C. $x=my$, where $y$ denotes the force, $x$ denotes the acceleration and $m$ denotes the constant mass$;$ $35$ newton
• D. $x=m$, where $y$ denotes the force, $x$ denotes the acceleration and $m$ denotes the constant mass$;$ $40$ newton

Answer 1

The correct option is B $y=mx$, where $y$ denotes the force, $x$ denotes the acceleration and $m$ denotes the constant mass$;$ $30$ newton

Let the force $=y$ and acceleration $=x$

Then $y\propto x\Rightarrow y=kx$, where $k$ is a constant of proportionality.

Here, $k=$ mass $=m=6$ kg

Therefore, the equation is $y=6x$.

From the graph, $y=30N$ when $x=5m/s^2$.