The force experienced by a moving electron which is entering into a condenser perpendicular to the direction of electric field having its plates 0.1m apart and potential difference of 300 V is
A
3.2×10−16N
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B
1.6×10−15N
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C
0.8×10−17N
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D
4.8×10−16N
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Solution
The correct option is D4.8×10−16N Electric field in the condenser ⇒E=3000.1V/m=3×103V/m So, Force experienced by electron =qE =1.6×10−19×3×103N =4.8×10−16N