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Question

The force F to be applied on the triangular block of mass M so that the block of mass m placed on it stationary with respect to wedge is
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A
mgtanθ
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B
(M+m)gtanθ
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C
(M+m)gcosθ
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D
(M+m)gsinθ
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Solution

The correct option is A (M+m)gtanθ
Correct option is (B) If block is stationary with respect to wedge acceleration of both a=FM+m Applying pseudo force: (FM+m)mcosθ=mgsinθacosθ=mmgsinθa=gtanθ so; a=F=(M+m)gtanθ

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