The force graphed in figure is applied horizontally to 5 kg cart, which then coasts up a ramp, as shown. The maximum height, y max, reached by the cart $(g = 10 m s^{- 2})$

1 m

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2 m

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3 m

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4 m

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Solution

The correct option is B 2 m
Total area under the curve gives the work done in moving the cart upto the top of the ramp.
Thus total work done= $\frac{1}{2} \times 4 \times 50 J = 100 J$
This work done goes into the gravitational potential energy gained by the cart= $m g h$
$⟹ m g h = 100 J$
$⟹ h = 2 m$

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The force graphed in figure is applied horizontally to 5 kg cart, which then coasts up a ramp, as shown. The maximum height, y max, reached by the cart (g=10ms−2)

The correct option is B 2 mTotal area under the curve gives the work done in moving the cart upto the top of the ramp.Thus total work done=12×4×50J=100JThis work done goes into the gravitational potential energy gained by the cart=mgh⟹mgh=100J⟹h=2m

The force graphed in figure is applied horizontally to 5 kg cart, which then coasts up a ramp, as shown. The maximum height, y max, reached by the cart $(g = 10 m s^{- 2})$