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Question

The force in the member CD of the truss as shown in figure below is

A
P (Tensile)
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B
2P (Tensile)
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C
zero
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D
P (Compression)
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Solution

The correct option is B 2P (Tensile)
Using method of joints,

FBA=FBD=0 [No force acting on joint B]

At joint A,
FH=0
FAD=2Psin 45o=(22P)
FAC=FAD cos 45o=22P.12=2P(Tensile)

HE=3P ()

MF=0

2P(2a)+P(a)=VE(a)

VE=5P ()

VF=5P ()

FCF cos 45o=FEF=HE=3P

FCF=32P(Compressive)

FCE=VE=5P (Tension)

Joint C

Fx=0

FCF cos 45o+FCD=P

32P.12+FCD=P

FCD=2P i.e., tensile

At joint D ,
FH=0
FCD=22P sin 450=2P (Tensile)

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