The Force of $500 N$ acts on body of mass $5 k g$ for $10 s e c$ . The change in momentum of body is

1000 N

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25000 N

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10000 N

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5000 N

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Solution

The correct option is D $5000 N$
$\begin{matrix} Δ P = F \cdot Δ T = 500 (10) = 5000 N \end{matrix}$
Hence,
option $(D)$ is correct answer.

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The Force of 500 N acts on body of mass 5 kg for 10 sec. The change in momentum of body is

The correct option is D 5000 NΔP=F⋅ΔT=500(10)=5000NHence,option (D) is correct answer.

The Force of $500 N$ acts on body of mass $5 k g$ for $10 s e c$ . The change in momentum of body is

The correct option is D $5000 N$
$\begin{matrix} Δ P = F \cdot Δ T = 500 (10) = 5000 N \end{matrix}$
Hence,
option $(D)$ is correct answer.