wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The force of attraction (A) between two objects, whose masses are fixed, varies inversely with the square of their distance of separation (d). The force of attraction between them is 2 units when the distance is 5 cm. What is the distance between the two two objects,if the attraction between them is 8 units?

Open in App
Solution

According to Newton law of Gravitation the force of attraction between two bodies is give by F = G m1m2/r^2

where m1 and m2 are the masses and r is the distance between them

therefore, 2 = Gm1m2/5^2 = Gm1m2/25 .............1)

Now if, F = 8 units, then

8 = Gm1m2/r^2 .......................2)

Dividing 2) by 1) we get,

8/2 = 25/r^2

4 = 25/r^2

r^2 = 25/4

r = 5/2 = 2.5 cm Ans.




flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Forces
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon