The force of gravity on a body of mass W on the surface of the earth is

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W \times g

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\frac{W}{g}

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W \times g^{2}

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Solution

The correct option is B $W \times g$
The force acting on an object of mass m on the earth's surface due to gravitational interaction with the earth has magnitude mg where g = 9.8 ms $^{2}$ .
So the force of gravity on a body of mass $W$ on the surface of the earth is $W \times g .$

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The force of gravity on a body of mass W on the surface of the earth is

The correct option is B W× gThe force acting on an object of mass m on the earth's surface due to gravitational interaction with the earth has magnitude mg where g = 9.8 ms2. So the force of gravity on a body of mass W on the surface of the earth is W×g.

The correct option is B $W \times g$
The force acting on an object of mass m on the earth's surface due to gravitational interaction with the earth has magnitude mg where g = 9.8 ms $^{2}$ .
So the force of gravity on a body of mass $W$ on the surface of the earth is $W \times g .$