The force of repulsion between two similar magnetic poles each of strength $2 A m$ at a distance $2 m$ from each other in vacuum is :

10^{- 5} N

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10^{- 7} N

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10^{- 3} N

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2 \times 10^{- 7} N

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Solution

The correct option is B $10^{- 7} N$
$P_{1} = P_{2} = 2 A m$
$r = 2 m .$
$F = \frac{μ_{o} P_{1} P_{2}}{4 π r^{2}}$
$R = \frac{4 π \times 10^{- 7} \times 2 \times 2}{4 π \times {(2)}^{2}}$
$F = 10^{- 7}$ N

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The force of repulsion between two similar magnetic poles each of strength 2 Am at a distance 2 m from each other in vacuum is :

The correct option is B 10−7N P1=P2=2 Amr=2m.F=μoP1P24πr2R=4π×10−7×2×24π×(2)2F=10−7N

The force of repulsion between two similar magnetic poles each of strength $2 A m$ at a distance $2 m$ from each other in vacuum is :

The correct option is B $10^{- 7} N$
$P_{1} = P_{2} = 2 A m$
$r = 2 m .$
$F = \frac{μ_{o} P_{1} P_{2}}{4 π r^{2}}$
$R = \frac{4 π \times 10^{- 7} \times 2 \times 2}{4 π \times {(2)}^{2}}$
$F = 10^{- 7}$ N