The force ofgravitation between two bodies of mass 1kg each separated by a distance of 1 m in vacuum is:

6.67 \times 10^{- 9} N

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6.67 \times 10^{- 10} N

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6.67 \times 10^{- 11} N

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6.67 \times 10^{- 12} N

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Solution

The correct option is C $6.67 \times 10^{- 11} N$
$F = \frac{G m_{1} m_{2}}{r^{2}}$
$= \frac{6.67 \times 10^{- 11} \times 1 \times 1}{(1)^{2}}$
$= 6.67 \times 10^{- 11} N$

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The force ofgravitation between two bodies of mass 1kg each separated by a distance of 1 m in vacuum is:

The correct option is C 6.67×10−11NF=Gm1m2r2 =6.67×10−11×1×1(1)2 =6.67×10−11N

The correct option is C $6.67 \times 10^{- 11} N$
$F = \frac{G m_{1} m_{2}}{r^{2}}$
$= \frac{6.67 \times 10^{- 11} \times 1 \times 1}{(1)^{2}}$
$= 6.67 \times 10^{- 11} N$