Question

The force on a particle of mass 10 g is (10 $\hat{i}$ + 5 $\hat{j}$)N. if it starts from rest, what would be its position at time t = 5s?

• A. 12500$\hat{i}$ + 6250$\hat{j}$ m
• B. 6250$\hat{i}$ + 12500$\hat{j}$ m
• C. 12500$\hat{i}$ + 12500$\hat{j}$ m
• D. 6250$\hat{i}$ + 6250$\hat{j}$ m

Answer 1

The correct option is A 12500$\hat{i}$ + 6250$\hat{j}$ m

We know that,

$f=ma(10i+5j)N=\left(10/1000\right)aa=500(2i+j)m/s^{2}s=ut+0.5a{t}^{2}s=\left(0\right)+0.5\left(500\right)(2i+j)\left(25\right)s=6250(2i+j)ms=12500i+6250jm$

A is the correct option.