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Question

The force required to move a body up a rough inclined plane is double the force required to prevent the body from sliding down the plane. The coefficient of friction when the angle of inclination of the plane is 60o, will be:

A
13
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B
12
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C
13
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D
12
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Solution

The correct option is B 13
Let the coefficient of friction be μ
Thus friction force acting f=μmg cos60o=μmg2
Upward motion : Friction force acts in downward direction
Fu=mgsin60o+f=32mg+μmg2=mg[3+μ2]

Downward motion : Friction force acts in upward direction
Fd=mgsin60of=32mgμmg2=mg[3μ2]

According to the question, Fu=2Fd

mg[3+μ2]= 2×mg[3μ2]

OR 3+μ=2[3μ] μ=13

509987_474689_ans_f81fa55f5d9e4a50900388a4a7ca1802.png

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