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Question

The formation of PH+4 is difficult as compared to NH+4 because:

A
The lone pair of phosphorous resides in almost a pure s orbital
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B
The lone pair of phosphorous resides in almost a pure p orbital
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C
The lone pair of phosphorous resides at a sp3 orbital
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D
The lone pair of phosphorous is optically inert
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Solution

The correct option is A The lone pair of phosphorous resides in almost a pure s orbital
..PH3+H+PH+4
According to Drago's rule, the lone pair on phosphorous resides in almost a pure s orbital. Due to the non-directional nature of s orbital, its overlapping tendency is greatly reduced in comparison to a lone pair present in a hybrid orbital, which is directional as present in ..NH3.

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