The formation of PH+4 is difficult compared to NH+4 because:
A
lone pair of phosphorous is optically inert.
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B
lone pair of phosphorous resides in almost pure p - orbital
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C
lone pair of phosphorous resides in sp3 orbital
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D
lone pair of phosphorous in almost pure s - orbital
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Solution
The correct option is D lone pair of phosphorous in almost pure s - orbital
According to Drago’s rule lone pair on phosphorous resides in almost pure – s – orbital, hence due to non – directional nature, its overlapping tendency is greatly reduced in comparison to a lone pair present in hybrid orbital, which is directional as present in