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Lewis Kossel Structure

The formula c...

Question

The formula charge on the nitrogen atoms from left to right the azide ion ${[N = N = N]}^{-}$ are:

+ 1, - 1, - 1

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- 1, + 1, - 1

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- 1, - 1, + 1

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- 2, + 1, 0

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Solution

The correct option is B $- 1, + 1, - 1$
Formal charge= (Number of valence $e^{-}$ in free neutral atom) $- \frac{1}{2}$ (Number of bonding $e^{-}$ ) $-$ (Number of non bonding $e^{-}$ )
Using above equation we can calculate formal charge on
$N_{I} = 5 - 2 - 4 = - 1$
$N_{I I} = 5 - 4 - 0 = + 1$
$N_{I I I} = 5 - 2 - 4 = - 1$

$N_{I} - 1 = N_{I I} + 1 = N_{I I I} - 1$

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