The formula for finding mean by direct method is - A - B - A Where B and A are respectively-A- class mark- frequency of the classB- Class size- average frequencyC- Frequency of the class- class markD- Average frequency- class size

The correct option is A class mark, frequency of the class x = ∑ fx/∑ f = ∑ (A × B)/∑ A Where B is the class mark. Class mark = 1/2 (upper limit of class + l ...

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Byju's Answer

Standard X

Mathematics

Mean of Ungrouped Data

The formula f...

Question

The formula for finding mean by direct method is $\frac{\sum (A \times B)}{\sum A}$

Where B and A are respectively:

Frequency of the class, class mark

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Class size, average frequency

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Average frequency, class size

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class mark, frequency of the class

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Solution

The correct option is D
class mark, frequency of the class

$¯ ¯ ¯ x$ = $\frac{\sum f x}{\sum f}$ = $\frac{\sum (A \times B)}{\sum A}$

Where B is the class mark.

Class mark = $\frac{1}{2}$ (upper limit of class + lower limit of class)

And A is the frequency of the class

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Similar questions

For finding mean by assumed mean method

$¯ ¯ ¯ x$ = a + $\frac{(\sum f \times d)}{\sum f}$

Where d and a are respectively

Q. If the class marks of a frequency distribution are

19.5, 26.5, 33.5, 40.5, 47.5, 54.5, 61.5

then find the size of the class and the classes.

Explain the meaning of each of the following terms.
(i) Variate
(ii) Class interval
(iii) Class size
(iv) Class mark
(v) Class limint
(vi) True class limits
(vii) Frequency of a class
(viii) Cumulative frequency of a class

Q. (a)The class interval having highest frequency is-
(b)The class-mark of class 50-60 is-
(c)The size of each class intervals is-

Q. The class marks of a frequency distribution are 47, 52, 57, 62, 67, 72, 77. Determine the (i) class size (ii) class limits with respect to the class mark 52 (iii) true class limits for class mark 52.

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The formula for finding mean by direct method is ∑(A×B)∑A Where B and A are respectively:

The correct option is D class mark, frequency of the class ¯¯¯x = ∑fx∑f = ∑(A×B)∑A Where B is the class mark. Class mark = 12 (upper limit of class + lower limit of class) And A is the frequency of the class

The formula for finding mean by direct method is $\frac{\sum (A \times B)}{\sum A}$

Where B and A are respectively:

The correct option is D
class mark, frequency of the class

$¯ ¯ ¯ x$ = $\frac{\sum f x}{\sum f}$ = $\frac{\sum (A \times B)}{\sum A}$

Where B is the class mark.

Class mark = $\frac{1}{2}$ (upper limit of class + lower limit of class)

And A is the frequency of the class