The formula mass of the complex CuSO 4 -5 H 2 O in grams is y - 10-22- Value of y is- given average atomic mass of Cu -63-5 u

Name: JEE - Grade 11 - Chemistry - Mole Concept - Session 03 - W21
Uploaded: 2022-07-04T10:36:42+05:30
Description: The atomic mass of nbsp;(Cu) = 63.5 u, (S) = 32 u, nbsp;(O) = 16 u and nbsp;(H) = 1 u So, the molecular mass of the complex CuSO_4.5H_2O = 249.56.022 × 10 ...

The atomic mass of nbsp;(Cu) = 63.5 u, (S) = 32 u, nbsp;(O) = 16 u and nbsp;(H) = 1 u So, the molecular mass of the complex CuSO_4.5H_2O = 249.56.022 × 10 ...

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Standard XII

Chemistry

Mole Concept

The formula m...

Question

The formula mass of the complex $C u S O_{4} .5 H_{2} O$ in grams is $y \times 10^{- 22}$ .
Value of $y$ is .
(given average atomic mass of $C u$ = 63.5 u)

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Solution

The atomic mass of $(C u)$ = 63.5 u, $(S)$ = 32 u, $(O)$ = 16 u and ( $H$ ) = 1 u
So, the molecular mass of the complex $C u S O_{4} .5 H_{2} O$
$= \frac{249.5}{6.022 \times 10^{23}} g = 4.14 \times 10^{- 22} g$
Hence $y = 4.14$

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The formula mass of the complex CuSO4.5H2O in grams is y×10−22. Value of y is . (given average atomic mass of Cu = 63.5 u)

The atomic mass of (Cu) = 63.5 u, (S) = 32 u, (O) = 16 u and (H) = 1 u So, the molecular mass of the complex CuSO4.5H2O =249.56.022×1023 g=4.14×10−22 g Hence y=4.14

The formula mass of the complex $C u S O_{4} .5 H_{2} O$ in grams is $y \times 10^{- 22}$ .
Value of $y$ is .
(given average atomic mass of $C u$ = 63.5 u)

The atomic mass of $(C u)$ = 63.5 u, $(S)$ = 32 u, $(O)$ = 16 u and ( $H$ ) = 1 u
So, the molecular mass of the complex $C u S O_{4} .5 H_{2} O$
$= \frac{249.5}{6.022 \times 10^{23}} g = 4.14 \times 10^{- 22} g$
Hence $y = 4.14$