Question

The formula mass of the complex $CuS{O}_4.5H_{2}O$ in grams is $y\times {10}^{-22}$.
Value of $y$ is .
(given average atomic mass of $Cu$ = 63.5 u)

Answer 1

The atomic mass of $\left(Cu\right)$ = 63.5 u, $\left(S\right)$ = 32 u, $\left(O\right)$ = 16 u and ($H$) = 1 u
So, the molecular mass of the complex $CuS{O}_4.5H_{2}O$
$=\frac{249.5}{6.022\times {10}^{23}}g=4.14\times {10}^{-22}g$
Hence $y=4.14$