The formula of a complex with composition $C r C l_{3} .6 H_{2} O$ giving the following observations :
Number of ions $= 3$ ; Number of $C l^{-}$ ions $= 2$ ; Number of non $-$ ionic Cl $= 1$ is :

[C r {(H_{2} O)}_{6}] C l_{3}

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[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O

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[C r C l_{2} {(H_{2} O)}_{4}] C l .2 H_{2} O

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[C r C l_{3} {(H_{2} O)}_{3}] .3 H_{2} O

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Solution

The correct option is B $[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O$
Complex is $[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O$ ; as in solution it gives ${[C r C l {(H_{2} O)}_{5}]}_{5}^{+ 2}$ and $2 C l^{-}$ ion.

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Similar questions

Q. When 1 mole of

C r C l_{3} .6 H_{2} O

is treated with excess of

A g N O_{3}

, 2 mol of AgCl are obtained. The formula of the complex is

When 0.2 mol $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 0.4 mol of AgCl are obtained. The formula of the complex is

Q. The modern formula of the above complexes based on the number of free

C l^{-}

ions per formula unit will be:

	Formula	Colour	$C l^{-}$ ions in solution per formula unit
(A)	$C r C l_{3} .6 H_{2} O$	violet	3
(B)	$C r C l_{3} .6 H_{2} O$	light green	2
(C)	$C r C l_{3}^{'} 6 H_{2} O$	dark green	1

When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3},$ 3 moles of AgCl are obtained. The formula of the complex is
(a) $[C r C l_{3} (H_{2} O)_{3}] 3 H_{2} O$
(b) $[C r C l_{3} (H_{2} O)_{4}] C l_{2} .2 H_{2} O$
(c) $[C r C l_{3} (H_{2} O)_{5}] C l_{2} . H_{2} O$
(d) $[C r (H_{2} O)_{6}] C l_{3}$

Q. Few isomers are given below. The correct statement regarding them are:
(i)

[C r (H_{2} O)_{6}] C l_{3}

(ii)

[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O

(iii)

[C r (H_{2} O)_{4} C l_{2}] C l .2 H_{2} O

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The formula of a complex with composition CrCl3.6H2O giving the following observations :Number of ions =3 ; Number of Cl− ions =2 ; Number of non − ionic Cl =1 is :

The correct option is B [CrCl(H2O)5]Cl2.H2OComplex is [CrCl(H2O)5]Cl2.H2O; as in solution it gives [CrCl(H2O)5]+2 and 2Cl− ion.

The formula of a complex with composition $C r C l_{3} .6 H_{2} O$ giving the following observations :
Number of ions $= 3$ ; Number of $C l^{-}$ ions $= 2$ ; Number of non $-$ ionic Cl $= 1$ is :

The correct option is B $[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O$
Complex is $[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O$ ; as in solution it gives ${[C r C l {(H_{2} O)}_{5}]}_{5}^{+ 2}$ and $2 C l^{-}$ ion.