The formula of a oxide of potassium with percentage of oxygen being $17.02 %$ is $K_{x} O_{y}$ .
Then, x+y =__________.

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Solution

The correct option is B 3
he formula of a oxide of potassium with percentage of oxygen being $17.02 %$ is $K_{2} O$ .
Here the percentage of oxygen is $\frac{16}{94} \times 100 = 17.2$ (16 is molecular weight of oxygen and 94 is the total molecular weight of $K_{2} O$ )
So x is 2 and y is 1
Then x+y is 3
hence option B is correct

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