The formula of a oxide of potassium with percentage of oxygen being $29.09 %$ is $K_{a} O_{b}$ .
Then, a+b =

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Solution

The correct option is B 4
The formula of a oxide of potassium with percentage of oxygen being $29.09 %$ is $K_{2} O_{2}$
Here the percentage of oxygen is $\frac{32}{110} \times 100 = 29.09$

Where,32 is molecular weight of oxygen and 110 is the total molecular weight of $(K_{2} O_{2})$
So, x is 2 y is 2
Then x+y is 4
hence option C is correct

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