Question

The formula of cyclic silicate in which 6 tetrahedra are arranged cyclically is:

• A. $S{i}_6{O}_{18}^{12-}$
• B. $S{i}_6{O}_{18}^{6-}$
• C. $S{i}_6{O}_6^{2-}$
• D. $S{i}_4{O}_{18}^{6-}$

Answer 1

The correct option is A $S{i}_6{O}_{18}^{12-}$

Cyclic silicates contain $(Si{O}_3{)}_n^{2n^{-}}$ or $(Si{O}_3^{2-}{)}_n$ ions which are formed by linking three or more tetrahedral $Si{O}_4^{4-}$ units cyclically. Each unit shares two oxygen atoms with other units. so, formula of cyclic silicate in which 6 tetrahedra are arranged cyclically is $S{i}_6{O}_{18}^{12-}.$