The formula of dichlorobis(urea)copper(II) is:

[C u (O = C (N H_{2})_{2})_{2}] C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C u C l_{2} (O = C (N H_{2})_{2})_{2}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C u (O = C (N H_{2})_{2})] C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C u C l_{2} (O = C (N H_{2})_{2}) H_{2}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[C u C l_{2} (O = C (N H_{2})_{2})_{2}]$
In this complex, 2 'chloro' ligands and 2 'urea' ligands are present. By following alphabetical order, chloro comes first with its number (i.e., dichloro) followed by the second ligand $(O = C (N H_{2})_{2})_{2}$ . Since, it is a bidentate ligand (i.e., can attach at more than one binding sites), the prefix 'bis' is used followed by the name of ligand urea. Cu oxidation state will be +2 ( $x - 2 = 0$ ). So, the correct answer is $[C u C l_{2} (O = C (N H_{2})_{2})_{2}]$ .

Suggest Corrections

Similar questions

C O_{2}, C u O, C a O

H_{2} O

Identify the correct order of acidic strength of $C O_{2}$ , $C u O$ , $C a O$ , and $H_{2} O$ :

C O_{2}, C u O, C a O

H_{2} O

C u O + H_{2} \to C u + H_{2} O

C u O

Join BYJU'S Learning Program