The formula of inorganic benzene is:

N₆H₆

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B₆H₆

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B₃C₃H₆

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B₃N₃H₆

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Solution

The correct option is D
B₃N₃H₆

Reaction of ammonia with diborane gives initially B₂H_6.2NH₃ which is formulated as [BH₂(NH₃)₂]⁺[BH₄]^- ; further heating gives borazine, B₃N₃H₆ known as inorganic benzene�.

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Similar questions

Benzene with molecular formula, C₆H₆, has

C_{6} H_{6}

C_{6} H_{6}

What is the empirical formula of C₂H₂ and C₆H₆?

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