The formula of iron (III) sulphate is:

F e_{3} C O_{4}

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F e_{2} (S O_{4})_{3}

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F e_{2} (C O_{4})_{3}

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F e C O_{4}

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Solution

The correct option is B $F e_{2} (S O_{4})_{3}$
It is given that the valency of iron in iron sulphate is $+ 3$ and we know that for sulphate $({S O_{4}}^{2 -})$ , it is $- 2$ . Therefore, the formula is $F e_{2} (S O_{4})_{3}$ .

$2 F e^{+ 3} + 3 {S O_{4}}^{- 2} \to F e_{2} (S O_{4})_{3}$
Iron (III) sulphate

Hence, option B is correct.

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Similar questions

Q. Formula for the following compound Iron (III)sulphate is

F e_{2} (S O_{4})_{3}

The formula of iron (III) sulphate is _______ .

Write the formulae for the following compounds:

Mercury(II) chloride

Nickel(II) sulphate

Tin(IV) oxide

Thallium(I) sulphate

Iron(III) sulphate

Chromium(III) oxide

Why is CuSO₄the expected formula of Copper Sulphate and not Cu₂SO₄ when Copper has variable valency of Cu⁺ and Cu²⁺ ; Here the higher valency is used for the salt.

However in the case of Iron Sulphate the expected formula is FeSO₄ and not Fe₂(SO₄)₃ eventhough Iron also has variable valency of Fe²⁺ and Fe³⁺ ; Here the lesser valency is used for the salt.

Q. Oxidation state of iron in

F e (C O)_{4}

is :

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The formula of iron (III) sulphate is:

The correct option is B Fe2(SO4)3It is given that the valency of iron in iron sulphate is +3 and we know that for sulphate (SO42−), it is −2. Therefore, the formula is Fe2(SO4)3.2Fe+3+3SO4−2→Fe2(SO4)3 Iron (III) sulphateHence, option B is correct.