The formula of the disilicate anion is:

S i O_{4}^{4 -}

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S i_{2} O_{7}^{6 -}

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S i_{2} O_{8}^{6 -}

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S i_{2} O_{9}^{6 -}

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Solution

The correct option is B $S i_{2} O_{7}^{6 -}$
Formula : $[S i_{2} O_{7}]^{6 -}$

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S i_{2} O_{7}^{6 -}

anion is obtained when :

$\begin{matrix} List I & List II A. B i^{3 +} ⟶ (B i O)^{+} & p. Heat B. [A l O_{2}]^{-} ⟶ A l (O H)_{3} & q. Hydrolysis C. S i O_{4}^{4 -} ⟶ S i_{2} O_{7}^{6 -} & r. Acidification D. (B_{4} O_{7}^{2 -}) ⟶ B (O H)_{3} & s. dilution by water \end{matrix}$

Q. Usually a disilicate shares only one oxygen of the silicate unit. But if in the disilicate unit, two O atoms are shared, then the formula of its salt with potassium will be:

Q. Which of the following silicate is called disilicate?

Q. The shape of orthosilicate ion

(S i O_{4}^{4 -})

is:

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The formula of the disilicate anion is:

The correct option is B Si2O6−7Formula : [Si2O7]6−

The correct option is B $S i_{2} O_{7}^{6 -}$
Formula : $[S i_{2} O_{7}]^{6 -}$