The formula of Young-s modulus Y of a wire- is given by Y-F-A-L- Lwhere- F is the force with which the wire is stretched- L the length- - L the change in length of wire and A the area of cross-section- The conversion factor to change it from CGS to MRS system is

The correct option is B 0.1Young's modulud of the wire, Y =F/A·L/Δ L 1 N = 10^5 dyne and 1 m = 100 cm Y=10^ 5N/10^ 4m^2= 0.1 N/m^2 ...

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Standard XII

Physics

Poisson's Effect

The formula o...

Question

The formula of Young's modulus Y of a wire, is given by $Y = \frac{F}{A} \times \frac{L}{Δ L}$
where, F is the force with which the wire is stretched, L the length, $Δ L$ the change in length of wire and A the area of cross-section. The conversion factor to change it from CGS to MRS system is

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Solution

The correct option is B 0.1
Young's modulud of the wire, $Y = \frac{F}{A} \cdot \frac{L}{Δ L}$
$1 N = 10^{5}$ dyne and 1 m = 100 cm
$Y = \frac{10^{- 5} N}{10^{- 4} m^{2}} = 0.1 N / m^{2}$

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The formula of Young's modulus Y of a wire, is given by Y=FA×LΔLwhere, F is the force with which the wire is stretched, L the length, ΔL the change in length of wire and A the area of cross-section. The conversion factor to change it from CGS to MRS system is

The correct option is B 0.1Young's modulud of the wire, Y=FA⋅LΔL1N=105 dyne and 1 m = 100 cmY=10−5N10−4m2=0.1N/m2

The formula of Young's modulus Y of a wire, is given by $Y = \frac{F}{A} \times \frac{L}{Δ L}$
where, F is the force with which the wire is stretched, L the length, $Δ L$ the change in length of wire and A the area of cross-section. The conversion factor to change it from CGS to MRS system is

The correct option is B 0.1
Young's modulud of the wire, $Y = \frac{F}{A} \cdot \frac{L}{Δ L}$
$1 N = 10^{5}$ dyne and 1 m = 100 cm
$Y = \frac{10^{- 5} N}{10^{- 4} m^{2}} = 0.1 N / m^{2}$