The forward and backward activation energy of exothermic reaction A - B is 80 and 280 kJ mol-1 respectively- The enthalpy change of the forward reaction A - B in kJ mol-1 will be-

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Standard XII

Chemistry

Methods for Ester Synthesis

The forward a...

Question

The forward and backward activation energy of exothermic reaction $A \to B$ is $80$ and $280 {kJ mol}^{- 1}$ respectively. The enthalpy change of the forward reaction $A \to B ({in kJ mol}^{- 1})$ will be:

- 80

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- 200

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- 280

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- 360

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Solution

The correct option is B $- 200$
The given reaction is exothermic reaction.

$E_{a_{F}} = Activation energy of the forward reaction$
$E_{a_{B}} = Activation energy of the backward reaction$

Enthalpy change can be expressed also in terms of activation energy
$Δ H = E_{a_{F}} - E_{a_{B}}$
$Δ H = E_{f} - E_{b}$
$Δ H = 80 - 280$
$Δ H = - 200 kJ/mol$

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The forward and backward activation energy of exothermic reaction A→B is 80 and 280 kJ mol−1 respectively. The enthalpy change of the forward reaction A→B (in kJ mol−1) will be:

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