The forward and backward activation energy of exothermic reaction A- B is 80 and 280 kJ mol-1 respectively- The enthalpy change of the forward reaction A - B in kJ-mol will be -

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Activation Energy

The forward a...

Question

The forward and backward activation energy of exothermic reaction $A \to B$ is $80 and 280 k J m o l^{- 1}$ respectively. The enthalpy change of the forward reaction $A \to B$ ( in $k J / m o l$ ) will be :

-200

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-360

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-280

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-80

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Solution

The correct option is A -200
The given reaction is an exothermic reaction

$E_{a_{F}}$ =Activation energy of the forward reaction
$E_{a_{B}}$ = Activation energy of the backward reaction

Enthalpy change can be expressed also in terms of activation energy,

$Δ H = E_{a_{F}} - E_{a_{B}}$

$Δ H = E_{f} - E_{b}$
$Δ H = 80 - 280$
$Δ H = - 200 k J / m o l$

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The forward and backward activation energy of exothermic reaction A→B is 80 and 280 kJ mol−1 respectively. The enthalpy change of the forward reaction A→B ( in kJ/mol) will be :

The correct option is A -200The given reaction is an exothermic reaction EaF =Activation energy of the forward reaction EaB= Activation energy of the backward reaction Enthalpy change can be expressed also in terms of activation energy, ΔH=EaF−EaB ΔH=Ef−Eb ΔH=80−280 ΔH=−200kJ/mol

The forward and backward activation energy of exothermic reaction $A \to B$ is $80 and 280 k J m o l^{- 1}$ respectively. The enthalpy change of the forward reaction $A \to B$ ( in $k J / m o l$ ) will be :