The four quantum numbers for the valence shell electron or last electron of sodium $(Z = 11)$ is :

n = 2, l = 1, m = - 1, s = - \frac{1}{2}

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n = 3, l = 0, m = 0, s = + \frac{1}{2}

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n = 3, l = 0, m = - 0, s = + \frac{1}{2}

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n = 3, l = 2, m = 2, s = + \frac{1}{2}

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Solution

The correct option is D $n = 3, l = 0, m = 0, s = + \frac{1}{2}$
$z = 11 = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
For $3 s^{1}$ ,
n = 3, $l = 0, m = 0,$ $s = + \frac{1}{2} o r - \frac{1}{2}$

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Similar questions

Which set of quantum numbers is possible for the last electron of Mg⁺ ion?

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

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