Question

The four quantum numbers of the valence electron of potassium are:

• A. $4,0,1,+\frac{1}{2}$
• B. $4,1,0,+\frac{1}{2}$
• C. $4,0,0,+\frac{1}{2}$
• D. $4,1,1,+\frac{1}{2}$

Answer 1

The correct option is C $4,0,0,+\frac{1}{2}$

For Potassium, configuration is $1s^{2}2s^2{p}^{6}3s^{2}3p^{6}4s^1$. The outermost electron is thus in 4s orbital unpaired.

The four quantum no. for the valence electron of potassium is
n=4, l=0, m=0 and s= +1/2
Hence, the correct option is C