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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

The four tyre...

Question

The four tyres of a motor car are filled with $c o_{2}, H e, H_{2}$ and $O_{2}$ respectively. The order in which they are to be re-inflated is:

C O_{2}, O_{2}, H e, H_{2}

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H_{2}, H e, O_{2}, C O_{2}

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H_{2}, H e, C O_{2}, O_{2}

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H_{2}, O_{2}, H e, C O_{2}

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Solution

The correct option is A $C O_{2}, O_{2}, H e, H_{2}$
Rate of diffusion of gas is inversely proportional to its molecular weight. Hence, higher the molecular weight, less it has to be re inflated.
Therefore the required order is:
$C O_{2} < O_{2} < H e < H_{2}$

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Similar questions

Q. Find the partial pressure of

{C O}_{2}

H_{2}

O_{2}

. Total pressure = 5 atm.

C O_{2}

= 5 moles,

H_{2}

= 3 moles,

O_{2}

= 2moles:

Q. If

C + O_{2} . ⟶ {C O}_{2} + 94.2 k c a l

H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} + 68.3 k c a l

{C H}_{4} + 2 O_{2} ⟶ {C O}_{2} + 2 H_{2} O + 210.8 k c a l

Then, the heat of formation of methane will be

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Q. If the four tubes of a car are filled to the same pressure with

N_{2}, O_{2}, H_{2}

and

C O_{2}

separately, then which one will be filled first?

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The four tyres of a motor car are filled with co2,He,H2 and O2 respectively. The order in which they are to be re-inflated is:

The correct option is A CO2,O2,He,H2Rate of diffusion of gas is inversely proportional to its molecular weight. Hence, higher the molecular weight, less it has to be re inflated.Therefore the required order is:CO2<O2<He<H2

The four tyres of a motor car are filled with $c o_{2}, H e, H_{2}$ and $O_{2}$ respectively. The order in which they are to be re-inflated is:

The correct option is A $C O_{2}, O_{2}, H e, H_{2}$
Rate of diffusion of gas is inversely proportional to its molecular weight. Hence, higher the molecular weight, less it has to be re inflated.
Therefore the required order is:
$C O_{2} < O_{2} < H e < H_{2}$