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Byju's Answer
Standard XII
Chemistry
1900's Physics and Wave
The fourth li...
Question
The fourth line of the Balmer series corresponds to electron transition between energy levels:
A
6 and 2
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B
5 and 2
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C
4 and 1
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D
5 and 1
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Solution
The correct option is
A
6 and 2
For Balmer series, transitions are made to second energy level, i.e,
n
1
=
2
∴
Fourth line is 6 to 2.
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Similar questions
Q.
Using Bohr's postulates, obtain the expression for the total energy of the electron in the stationary states of the hydrogen atom. Hence draw the energy level diagram showing how the line spectra corresponding to Balmer series occur due to transition energy levels .
Q.
The Third Line in Balmer series correspondence to an electronic transition between which Bohr's orbits in hydrogen:
Q.
The energy of the electron of the hydrogen atom in the
n
t
h
orbit is
E
n
=
−
13.6
n
2
e
V
. Draw the energy level diagram for the hydrogen atom and show transitions corresponding to lives of Lyman and Balmer series.
Q.
Which of the following transition corresponds to the second line in Balmer series?
Q.
The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns the lowest orbit while Balmer series is formed when the electron returns to the second orbit. Similarly, Paschen, Brackett, and Pfind series are formed when electron returns to the third, fourth, and fifth from higher orbits, respectively.
Maximum number of lines produced when an electron jumps from nth level to ground level is equal to
n
(
n
−
1
)
2
.
If the electron comes back from the energy level having energy E
2
to the energy level having energy E
1
, then difference may be expressed in terms of energy of photon as
E
2
- E
1
=
Δ
E,
λ
= hc/
Δ
E
Since h and c are constant,
Δ
E corresponds to definite energy, thus, each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.
Wave number of line is given by the formula
v =
R
Z
2
(
1
n
2
1
−
1
n
2
2
)
where R is a Rydberg constant.
The wave number of electromagnetic radiation emitted during the transition of electron in between the two levels of Li
2
+
ion whose principal quantum numbers sum is 4 and difference is 2 is :
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