The fourth term in the expansion of 1-2 x 3-2 will beA- -3-4 x4B- x3-2C- -x3-2D- 3-4 x4

The correct option is B Expansion of (1 2x)^ 3/2 = 1 + nbsp;3/2( 2x) + nbsp; 3/2. 1/2.1/2( 2x)^2 nbsp;+ nbsp; 3/2. 1/2( 1/2) 1/6( 2x)^3 + ......... ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Mathematics

Sum of product of binomial coefficients

The fourth te...

Question

The fourth term in the expansion of $(1 - 2 x)^{\frac{3}{2}}$ will be

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

Expansion of $(1 - 2 x)^{\frac{3}{2}}$

= $1 + \frac{3}{2} (- 2 x) + \frac{3}{2} . \frac{1}{2} . \frac{1}{2} (- 2 x)^{2} + \frac{3}{2} . \frac{1}{2} (- \frac{1}{2}) \frac{1}{6} (- 2 x)^{3} + . . . . . . . . .$

Hence $4^{t h}$ term is $\frac{x^{3}}{2}$

Suggest Corrections

Similar questions

Q. The fourth term in the expansion of

(1 - 2 x)^{\frac{3}{2}}

will be

Find the middle terms in the expansion of ${(3 x - \frac{x^{3}}{6})}^{7}$

Find the fourth term from the end in the expansion of ${(\frac{3}{x^{2}} - \frac{x^{3}}{6})}^{7}$

Q. The derivative of

(x^{3} + ln 6) (\sqrt{x})

will be

Q. Match the following.

	Column - I		Column - II
(P)	$(x^{2} + 5) (x^{3} + 3) + 5$	(1)	${- x}^{3} - 3 x^{2} + 3 x + 2$
(Q)	$(\frac{- 10}{3} x y^{3}) \times (\frac{6}{5} x^{3} y)$	(2)	$- x^{3} + x^{2} + 3 x - 6$
(R)	$(x^{3} - x^{2} - x - 2) - (2 x^{3} + 2 x^{2} - 4 x - 4)$	(3)	$x^{5} + 5 x^{3} + 3 x^{2} + 20$
(S)	$(x^{3} - x^{2} - x - 2) + (2 x^{2} - 2 x^{3} + 4 x - 4)$	(4)	$- 4 x^{4} y^{4}$

Q. Simplify the expression:

(2 x^{3} + 4) \div 2

Join BYJU'S Learning Program

The fourth term in the expansion of (1−2x)32 will be

The correct option is B Expansion of (1−2x)32 = 1+32(−2x)+32.12.12(−2x)2+32.12(−12)16(−2x)3+......... Hence 4th term is x32

The fourth term in the expansion of $(1 - 2 x)^{\frac{3}{2}}$ will be

The correct option is B

Expansion of $(1 - 2 x)^{\frac{3}{2}}$

= $1 + \frac{3}{2} (- 2 x) + \frac{3}{2} . \frac{1}{2} . \frac{1}{2} (- 2 x)^{2} + \frac{3}{2} . \frac{1}{2} (- \frac{1}{2}) \frac{1}{6} (- 2 x)^{3} + . . . . . . . . .$

Hence $4^{t h}$ term is $\frac{x^{3}}{2}$