Question

The fourth term of an AP is $0$ and its ${25}^{th}$ term is $x$ times of its ${11}^{th}$ term. Find $x$.

Answer 1

$4$th term of A.D $=0$

$a+3d=0a=-3d25thterm=x\left(11thterm\right)a+24d=x(a+10d)21d=x\left(7d\right)x=3$