The fourth term of an arithmetic progression is 8. What is the sum of first 7 terms of the arithmetic progression?

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Solution

The correct option is C 56
Fourth term = 8 $\to$ a + 3d = 8

Sum of seven terms

$= S_{7} = \frac{7}{2} \times [2 a + (7 - 1) d]$
$= \frac{7}{2} \times 2 (a + 3 d)$
$= 7 \times 8 = 56$

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The fourth term of an arithmetic progression is 8. What is the sum of first 7 terms of the arithmetic progression?

The correct option is C 56Fourth term = 8 → a + 3d = 8 Sum of seven terms =S7=72×[2a+(7−1)d] =72×2(a+3d) =7×8=56

The correct option is C 56
Fourth term = 8 $\to$ a + 3d = 8

Sum of seven terms

$= S_{7} = \frac{7}{2} \times [2 a + (7 - 1) d]$
$= \frac{7}{2} \times 2 (a + 3 d)$
$= 7 \times 8 = 56$