The KP-KC ratio will be highest in case of

Using the relation K_P = K_C(RT)^Δ n, we get K_P/K_C = (RT)^Δ n Thus K_P/K_C will be highest for the reaction having highest value of Δ n. The Δ n. values for v ...

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Byju's Answer

Standard XII

Chemistry

Relation between Kp and Kc

The KP/KC rat...

Question

The $\frac{K_{P}}{K_{C}}$ ratio will be highest in case of

$C O (g) + \frac{1}{2} O_{2} (g) ⇌ C O_{2} (g)$

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$H_{2} (g) + I_{2} (g) ⇌ 2 H l (g)$

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$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$

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$7 H_{2} (g) + 2 N O_{2} (g) ⇌ 2 N H_{3} (g) + 4 H_{2} O (g)$

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Solution

The correct option is C
$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$

Using the relation $K_{P} = K_{C} (R T)^{Δ n}$ , we get
$\frac{K_{P}}{K_{C}} = (R T)^{Δ n}$
Thus $\frac{K_{P}}{K_{C}}$ will be highest for the reaction having highest value of $Δ n$ .
The $Δ n$ . values for various reactions are
(a) $Δ n = 1 - (1 + \frac{1}{2}) = - \frac{1}{2}$
(b) $Δ n = 2 - (1 + 1) = 0$
(c) $Δ n = (1 + 1) - 1 = 1$
(d) $Δ n = (2 + 4) - (7 + 2) = - 3$
Thus maximum value of $Δ n = 1$

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Similar questions

The $\frac{K_{P}}{K_{C}}$ ratio will be highest in case of

Q. In which of the following reaction, the value of

K_{p}

will be equal to

K_{c}

\frac{K_{p}}{K_{c}}

for the following reaction will be:

C O (g) + O_{2} (g) ⇌ C O_{2} (g)

The relation between equilibrium constant $K_{P}$ and $K_{C}$ is

\frac{K_{p}}{K_{c}}

for the following reaction will be

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)

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The KPKC ratio will be highest in case of

The $\frac{K_{P}}{K_{C}}$ ratio will be highest in case of