The fraction 2(√2 + √6)/3(√2+3) is equal to.

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Solution

2(√2 + √6)/3(√2+3)

(2√2 + 2√6)/(3√2+9)

(2√2 + 2√6)(9-3√2) / (9+3√2) (9-3√2)

2√2 (1+√3)(9-3√2)/ 81-18

2√2 (1+√3) 3(3-√2)/ 63

6√2 (1+√3)(3-√2)/ 63

2√2(1+√3)(3-√2) / 21

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Similar questions

Q. The fraction

\frac{2 (\sqrt{2} + \sqrt{6})}{3 (\sqrt{2 + \sqrt{3}})}

is equal to _________

Q. The fraction

\frac{\sqrt{3} - \sqrt{2}}{\sqrt{2}}

is equal to

The numerator of a fraction is 6 less than the denominator. If 3 is added to the numerator, the fraction is equal to $\frac{2}{3}$ . What is the original fraction equal to ?

Q. The numerator of a fraction is

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less than the denominator. If

3

is added to the numerator, the fraction is equal to

\frac{2}{3}

, find the original fraction

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less then the denomiator. If

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is added to the numerator, the fraction becomes equal to

\frac{2}{3}

. Find the original fraction.

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The fraction 2(√2 + √6)/3(√2+3) is equal to.

2(√2 + √6)/3(√2+3) (2√2 + 2√6)/(3√2+9) (2√2 + 2√6)(9-3√2) / (9+3√2) (9-3√2) 2√2 (1+√3)(9-3√2)/ 81-18 2√2 (1+√3) 3(3-√2)/ 63 6√2 (1+√3)(3-√2)/ 63 2√2(1+√3)(3-√2) / 21

2(√2 + √6)/3(√2+3)

(2√2 + 2√6)/(3√2+9)

(2√2 + 2√6)(9-3√2) / (9+3√2) (9-3√2)

2√2 (1+√3)(9-3√2)/ 81-18

2√2 (1+√3) 3(3-√2)/ 63

6√2 (1+√3)(3-√2)/ 63

2√2(1+√3)(3-√2) / 21